HandbookDevelopment Length & Lap Length

Development Length & Lap Length

IS 456:2000 · Clause 26.2.1 — Development of Stress in Reinforcement
Development length (Ld) is the minimum length of bar required to develop its full design stress. Lap length is the overlap needed to transfer stress between two bars. Per IS 456, Ld = (ϕ × σs) / (4 × τbd).
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Formula (IS 456 Clause 26.2.1)
Ld = (ϕ × σs) / (4 × τbd)
Where ϕ = bar diameter (mm), σs = stress in bar (0.87 × fy for limit state), τbd = design bond stress (Table 26 of IS 456)
Quick Calculator
Steel Grade
Bar Diameter
Concrete Grade
Dev. Length (Ld)
1032
mm (tension)
Lap (Tension)
1032
mm
Lap (Comp.)
826
mm
16mm ϕ · Fe 415 · M25 · σs = 361 MPa
Fe 415 — Ld in mm (tension)
Bar Dia (mm)M20M25M30M35M40
8 mm602516481425380
10 mm752645602531475
12 mm903774722637570
16 mm12041032963849760
20 mm1505129012041062950
25 mm18811613150413271187
28 mm21071806168514861330
32 mm24082064192616991520
Design Bond Stress τbd (IS 456 Table 26)
Gradeτbd (N/mm²)Note
M201.2For plain bars, multiply by 0.625
M251.4
M301.5
M351.7
M401.9
M452
M502.1
Lap Length Rules
Tension — bars in contact
Ld or 30ϕ (whichever is greater)
Tension — bars NOT in contact
Ld or 30ϕ + gap
Compression
Ld or 24ϕ (whichever is greater)
>50% bars lapped at one section
1.3 × Ld
Flexural tension zone, >50% lapped
2.0 × Ld
Practical Notes
Compression Ld = 80% of tension Ld (Clause 26.2.1)
Deformed bars: Ld values above apply. For plain bars: multiply by 1.6
Increase Ld by 50% at top of pour (top bars) — reduced bond due to bleed water
Stagger laps: no more than 50% bars lapped at same section
Laps not permitted at sections of maximum stress
Minimum lap = 200mm or 15ϕ, whichever is greater
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