Design Rules🏛 Structural — RCC

Tension Lap Length — Fe500 in M25

Lap length for tension bars in Fe500 deformed reinforcement
See also📖 IS 456🔗 IS 456🔗 IS 13920🧮 RCC Design📒 Handbook Topic
50
× bar diameter
≈ 800 mm for 16 mm bar (Fe500 / M25)
50 dlap lengthFE500 / M25TENSION LAP
Primary value50 × bar diameter (≈ 800 mm for 16 mm bar (Fe500 / M25))
Applies toFe500 deformed bars in tension · M25 grade concrete · Splices in slab and beam main reinforcement
ExceptionsFe500 / M2057 d
Fe500 / M3041 d
Fe415 / M2541 d
Compression lap (any grade)Use Ld for compression — typically 30–40 d
Splice in zone of high stressIncrease 25% (Cl. 26.2.5.1)
Measured asLap length is measured from the end of one bar to the end of the lapping bar — the full overlap. For deformed bars in tension, lap length equals development length Ld unless lap zone is in high stress.
SourceIS 456Clause 26.2.5.1, 26.2.1.1
✓ Verified

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Why this matters

Lap splicing transfers force between two bars by bond — the bond strength of Fe500 in M25 works out to a bar-diameter multiplier of ~50 by the IS 456 formula Ld = φσs / (4τbd). Going shorter relies on the bar to slip without breaking, which the code explicitly forbids for tension splices.

Typical practice

Estimators and BBS engineers default to 50d for Fe500/M25 throughout the BBS without checking grade-by-grade — adequate for 95% of residential work. Lap zones are staggered so no more than 50% of bars are spliced at any cross-section, per Cl. 26.2.5.1.

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